(A) The diameter of the wheel is $d = 1 \ m$,so the radius is $r = \frac{d}{2} = 0.5 \ m$.The frequency of rotation is $f = 30 \ \text{rev/s}$.The ang

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The diameter of the wheel is $d = 1 \ m$,so the radius is $r = \frac{d}{2} = 0.5 \ m$.The frequency of rotation is $f = 30 \ \text{rev/s}$.The angular velocity $\omega$ is given by $\omega = 2 \pi f = 2 \pi \times 30 = 60 \pi \ \text{rad/s}$.The linear speed $v$ of a point on the circumference is given by the relation $v = r \omega$.Substituting the values,we get $v = 0.5 \times 60 \pi = 30 \pi \ m/s$.

Class 11 Physics 3-2.Motion in Plane Kinematics Circular Motion (Uniform Angular Accelaration)

Easy

$A$ wheel has a diameter of $1 \ m$. If it makes $30$ revolutions per second,then the linear speed of a point on its circumference will be:

A
$30 \pi \ m/s$
B
$\pi \ m/s$
C
$60 \pi \ m/s$
D
$\frac{\pi}{2} \ m/s$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

3-2.Motion in Plane

Subtopic

Kinematics Circular Motion (Uniform Angular Accelaration)

$A$ wheel rotates with a constant acceleration of $2.0 \ rad/s^2$. If the wheel starts from rest,the number of revolutions it makes in the first ten seconds is:

Medium

View Solution

$A$ fan starts from rest and makes $10$ revolutions in the first $3$ seconds. Assuming constant angular acceleration,how many revolutions will it make in the next $3$ seconds?

Difficult

View Solution

The angular acceleration of a wheel is $3 \ rad/s^2$. If its initial angular velocity is $2 \ rad/s$,what is the angular displacement (in $rad$) covered by it in $2 \ s$?

Easy

View Solution

$A$ body is revolving with a uniform speed $v$ in a circle of radius $r$. The tangential acceleration is

Easy

View Solution

Certain neutron stars are believed to be rotating at about $1 \, rev/sec$. If such a star has a radius of $20 \, km$,the acceleration of an object on the equator of the star will be:

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ wheel has a diameter of $1 \ m$. If it makes $30$ revolutions per second,then the linear speed of a point on its circumference will be:

Similar Questions

$A$ wheel rotates with a constant acceleration of $2.0 \ rad/s^2$. If the wheel starts from rest,the number of revolutions it makes in the first ten seconds is:

$A$ fan starts from rest and makes $10$ revolutions in the first $3$ seconds. Assuming constant angular acceleration,how many revolutions will it make in the next $3$ seconds?

The angular acceleration of a wheel is $3 \ rad/s^2$. If its initial angular velocity is $2 \ rad/s$,what is the angular displacement (in $rad$) covered by it in $2 \ s$?

$A$ body is revolving with a uniform speed $v$ in a circle of radius $r$. The tangential acceleration is

Certain neutron stars are believed to be rotating at about $1 \, rev/sec$. If such a star has a radius of $20 \, km$,the acceleration of an object on the equator of the star will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module