A weak acid HX (K_a = 10^{-5}) on reaction wi | vedclass

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(B) For the salt $NaX$,which is a salt of a weak acid and a strong base,the hydrolysis reaction is:$X^{-} + H_2O \rightleftharpoons HX + OH^{-}$The hy

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$0.01$

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(B) For the salt $NaX$,which is a salt of a weak acid and a strong base,the hydrolysis reaction is:$X^{-} + H_2O ightleftharpoons HX + OH^{-}$The hydrolysis constant $K_h$ is given by $K_h = \frac{K_w}{K_a} = \frac{10^{-14}}{10^{-5}} = 10^{-9}$.The degree of hydrolysis $h$ is given by the formula $h = \sqrt{\frac{K_h}{C}}$,where $C = 0.1 \ M$.Substituting the values:$h = \sqrt{\frac{10^{-9}}{0.1}} = \sqrt{10^{-8}} = 10^{-4}$.The percentage of hydrolysis is calculated as:$\% h = h 	imes 100 = 10^{-4} 	imes 100 = 10^{-2} = 0.01 \ \%$.

$A$ weak acid $HX$ $(K_a = 10^{-5})$ on reaction with $NaOH$ gives $NaX$. For $0.1 \ M$ aqueous solution of $NaX$,the $\%$ hydrolysis is $....... \ \%$.

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