(D) Let the total capacity of the tank be $1$ unit.Rate of filling by tap $A = \frac{1}{4}$ unit per hour.Rate of filling by tap $B = \frac{1}{6}$ uni

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(D) Let the total capacity of the tank be $1$ unit.Rate of filling by tap $A = \frac{1}{4}$ unit per hour.Rate of filling by tap $B = \frac{1}{6}$ unit per hour.Rate of emptying by tap $C = \frac{1}{3}$ unit per hour.When all three taps are opened simultaneously,the net rate of filling is:$= \left(\frac{1}{4} + \frac{1}{6} - \frac{1}{3}\right)$ unit per hour.$= \left(\frac{3 + 2 - 4}{12}\right) = \frac{1}{12}$ unit per hour.Therefore,the time required to fill the tank completely is the reciprocal of the net rate:$= \frac{1}{1/12} = 12$ $hours$.

Competitive Quantitative Aptitude Pipes and Cistern Pipes and Cistern

Easy

$A$ water tank has three taps $A$,$B$ and $C$. Tap $A$,when opened,can fill the water tank alone in $4$ $hours$. Tap $B$,when opened,can fill the water tank alone in $6$ $hours$. Tap $C$,when opened,can empty the water tank alone in $3$ $hours$. If taps $A$,$B$ and $C$ are opened simultaneously,how long will it take to fill the tank completely? (in $hours$)

A
$10$
B
$8$
C
$18$
D
$12$

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Pipes and Cistern

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Pipes and Cistern

Pipe $X$ can fill a tank in $20$ $hours$ and pipe $Y$ can fill the tank in $35$ $hours.$ Both the pipes are opened on alternate hours. Pipe $Y$ is opened first,then in how much time (in hours) will the tank be full?

Medium

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$A, B$ and $C$ are three pipes connected to a tank. $A$ and $B$ together fill the tank in $6$ $hrs$. $B$ and $C$ together fill the tank in $10$ $hrs$,and $C$ and $A$ together fill the tank in $7 \frac{1}{2}$ $hrs$. In how much time (in $hours$) will $A, B$ and $C$ fill the tank together?

Easy

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$A, B$ and $C$ are three pipes connected to a tank. $A$ and $B$ together fill the tank in $6 \text{ h}$,$B$ and $C$ together fill the tank in $10 \text{ h}$ and $A$ and $C$ together fill the tank in $12 \text{ h}$. In how much time will $A, B$ and $C$ fill up the tank together?

Medium

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$A$ tank has two pipes. The first pipe can fill it in $45$ minutes and the second can empty it in $1$ hour. In what time will the empty tank be filled if the pipes are opened one at a time in alternate minutes?

Medium

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One tap can fill a cistern in $2$ hours and another can empty the cistern in $3$ hours. How long will it take to fill the cistern if both the taps are opened (in $\text{hours}$)?

Easy

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Pipe $X$ can fill a tank in $20$ $hours$ and pipe $Y$ can fill the tank in $35$ $hours.$ Both the pipes are opened on alternate hours. Pipe $Y$ is opened first,then in how much time (in hours) will the tank be full?

$A, B$ and $C$ are three pipes connected to a tank. $A$ and $B$ together fill the tank in $6$ $hrs$. $B$ and $C$ together fill the tank in $10$ $hrs$,and $C$ and $A$ together fill the tank in $7 \frac{1}{2}$ $hrs$. In how much time (in $hours$) will $A, B$ and $C$ fill the tank together?

$A, B$ and $C$ are three pipes connected to a tank. $A$ and $B$ together fill the tank in $6 \text{ h}$,$B$ and $C$ together fill the tank in $10 \text{ h}$ and $A$ and $C$ together fill the tank in $12 \text{ h}$. In how much time will $A, B$ and $C$ fill up the tank together?

$A$ tank has two pipes. The first pipe can fill it in $45$ minutes and the second can empty it in $1$ hour. In what time will the empty tank be filled if the pipes are opened one at a time in alternate minutes?

One tap can fill a cistern in $2$ hours and another can empty the cistern in $3$ hours. How long will it take to fill the cistern if both the taps are opened (in $\text{hours}$)?

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