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(B) For a concave mirror,the radius of curvature $R = -36 \ cm$ (by sign convention). Therefore,the focal length $f = R/2 = -18 \ cm$. Since the image

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$12$

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(B) For a concave mirror,the radius of curvature $R = -36 \ cm$ (by sign convention). Therefore,the focal length $f = R/2 = -18 \ cm$. Since the image is virtual and magnified three times,the magnification $m = +3$. The formula for magnification in terms of focal length and object distance $u$ is $m = f / (f - u)$. Substituting the values: $3 = -18 / (-18 - u)$. Multiplying both sides: $3(-18 - u) = -18$. $-54 - 3u = -18$. $-3u = 54 - 18 = 36$. $u = -12 \ cm$. The distance of the object from the mirror is $12 \ cm$.

$A$ virtual image three times the size of the object is obtained with a concave mirror of radius of curvature $36 \ cm$. The distance of the object from the mirror is ........ $cm$.

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