Incident parallel rays make an angle of 5^{ci | vedclass

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Question

(B) For a concave mirror,parallel rays incident at an angle $	heta$ with the principal axis focus on the focal plane at a distance $y$ from the axis.

Vedclass · Accepted Answer

$1.75$

Vedclass · Answer

(B) For a concave mirror,parallel rays incident at an angle $	heta$ with the principal axis focus on the focal plane at a distance $y$ from the axis.Using the small angle approximation,the distance $y$ from the axis is given by $y = f 	an 	heta$.Given $f = 20 \ cm$ and $	heta = 5^{\circ}$.Converting the angle to radians: $	heta = 5 	imes \frac{\pi}{180} \approx 0.0873 \ rad$.Since $	an 	heta \approx 	heta$ for small angles,$y = 20 	imes (5 	imes \frac{\pi}{180})$.$y = 20 	imes 0.08726 = 1.745 \ cm$.Rounding to the nearest value,$y \approx 1.75 \ cm$.

Incident parallel rays make an angle of $5^{\circ}$ with the axis of a concave mirror of focal length $20 \ cm$. The perpendicular distance of the image from the axis is nearly $-$ (in $cm$)

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