$A$ value of $\alpha$ such that $\int_{\alpha}^{\alpha+1} \frac{dx}{(x+\alpha)(x+\alpha+1)} = \log_{e}\left(\frac{9}{8}\right)$ is

  • A
    $-\frac{1}{2}$
  • B
    $-2$
  • C
    $\frac{1}{2}$
  • D
    $2$

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