A transformer has a turn ratio of 100/1. If t | vedclass

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(B) For an ideal transformer,the relationship between currents and the number of turns is given by the formula: $\frac{i_p}{i_s} = \frac{N_s}{N_p}$.Gi

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$0.04$

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(B) For an ideal transformer,the relationship between currents and the number of turns is given by the formula: $\frac{i_p}{i_s} = \frac{N_s}{N_p}$.Given that the turn ratio is $\frac{N_p}{N_s} = \frac{100}{1}$,we have $\frac{N_s}{N_p} = \frac{1}{100}$.The current in the secondary coil is $i_s = 4 \, A$.Substituting these values into the formula: $\frac{i_p}{4} = \frac{1}{100}$.Therefore,$i_p = \frac{4}{100} = 0.04 \, A$.

$A$ transformer has a turn ratio of $100/1$. If the secondary coil has a $4 \, A$ current,then the current in the primary coil is......$A$

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