$A$ train $110 \;m$ long is running with a speed of $60 \;km/h$. In what time (in $seconds$) will it pass a man who is running at $6 \;km/h$ in the direction opposite to that in which the train is going?

$A$ $270 \;m$ long train running at a speed of $120 \;km/hr$ crosses another train running in the opposite direction at a speed of $80 \;km/hr$ in $9 \;seconds$. What is the length (in $m$) of the other train?

How many seconds will a train $60 \; m$ in length,travelling at the rate of $42 \; km/h$,take to pass another train $84 \; m$ long,proceeding in the same direction at the rate of $30 \; km/h$?

$A$ train covers a distance of $12 \;km$ in $10 \;minutes$. If it takes $6$ seconds to pass a telegraph post,then the length of the train (in $m$) is:

Two stations $P$ and $Q$ are $110 \; km$ apart on a straight line. One train starts from $P$ at $7 \; am$ and travels towards $Q$ at $20 \; km/h$ speed. Another train starts from $Q$ at $8 \; am$ and travels towards $P$ at a speed of $25 \; km/h$. At what time will they meet?

$A$ train $120 \; m$ long moving at a speed of $60 \; km/hr$ crosses a train $130 \; m$ long coming from the opposite direction in $6 \; seconds$. The speed of the second train is (in $km/hr$):