A trader marked his goods at 20 % above the c | vedclass

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Question

Here, Total discount on $MP$

$=\left[\frac{1}{2} 	imes 0+\frac{1}{4} 	imes 20+\frac{1}{4} 	imes 40ight] \%$

[where half is sold at $MP,$ on

Vedclass · Accepted Answer

$2$

Vedclass · Answer

Here, Total discount on $MP$

$=\left[\frac{1}{2} 	imes 0+\frac{1}{4} 	imes 20+\frac{1}{4} 	imes 40ight] \%$

[where half is sold at $MP,$ one$-$fourth $20\%$ discount, one$-$fourth $40 \%$ discount $]=15 \%$

Now, If $C P$ (assume) $=$ $Rs.$ $x$

then $MP =20 \%$ above $CP = Rs .1 .2 x$

$MP$ after $15 \%$ discount $=85 \%$ of $1.2 x=$ $Rs.$ $1.02 x$

$\operatorname{Gain} \%=\frac{1.02 x-x}{x} 	imes 100=2 \%$

A trader marked his goods at $20 \%$ above the cost price. He sold half the stock at the marked price, one quarter at a discount of $20 \%$ on the marked price and the rest at a discount of $40 \%$ on the marked price. His total gain is in $\%$?

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