A telescope has an objective lens of 10, cm d | vedclass

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(C) The angular resolution of a telescope is given by $	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light and $D$ is the diam

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$5\, mm$

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(C) The angular resolution of a telescope is given by $	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength of light and $D$ is the diameter of the objective lens.Given: $\lambda = 5000\,\mathring{A} = 5 	imes 10^{-7}\,m$,$D = 10\,cm = 0.1\,m$,and distance $L = 1\,km = 10^3\,m$.The minimum distance $x$ between two objects that can be resolved is given by $x = L 	heta = \frac{1.22 \lambda L}{D}$.Substituting the values: $x = \frac{1.22 	imes (5 	imes 10^{-7}\,m) 	imes (10^3\,m)}{0.1\,m}$.$x = \frac{1.22 	imes 5 	imes 10^{-4}}{10^{-1}} = 1.22 	imes 5 	imes 10^{-3}\,m = 6.1 	imes 10^{-3}\,m = 6.1\,mm$.The order of magnitude is approximately $5\,mm$.

$A$ telescope has an objective lens of $10\, cm$ diameter and is situated at a distance of $1\, km$ from two objects. The minimum distance between these two objects which can be resolved by the telescope,when the mean wavelength of light is $5000\,\mathring{A}$,is the order of

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