(B) For $D.C.$ supply,the coil acts as a pure resistor because the frequency is $0$. $R = \frac{V}{I_{DC}} = \frac{100}{25} = 4\, \Omega$. For $A.C.$

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(B) For $D.C.$ supply,the coil acts as a pure resistor because the frequency is $0$. $R = \frac{V}{I_{DC}} = \frac{100}{25} = 4\, \Omega$. For $A.C.$ supply,the coil has both resistance $R$ and inductive reactance $X_L$. The impedance $Z$ is given by $Z = \frac{V}{I_{AC}} = \frac{100}{20} = 5\, \Omega$. Since $Z^2 = R^2 + X_L^2$,we have $X_L = \sqrt{Z^2 - R^2}$. $X_L = \sqrt{5^2 - 4^2} = \sqrt{25 - 16} = \sqrt{9} = 3\, \Omega$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

$A$ student connects a long air-cored coil of manganin wire to a $100\, V$ $D.C.$ supply and records a current of $25\, A$. When the same coil is connected across a $100\, V$,$50\, Hz$ $A.C.$ supply,the current reduces to $20\, A$. The reactance of the coil is ...... $\Omega$.

A
$4$
B
$3$
C
$5$
D
None

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Data Entry - Chemistry

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Level 0 of all question bank

$A$ liquid does not wet the solid surface if the angle of contact is

TS EAMCET 2007

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Which of the following orders is incorrect?

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List-$I$ shows reactions involved in the metallurgy of $Pb$ (lead) and List-$II$ shows the names of the processes. Match List-$I$ with List-$II$ and select the correct code for your answer.

List-$I$ List-$II$

$(P). PbS + 2PbO \xrightarrow{\Delta} 3Pb + SO_2 \uparrow$ $(1).$ Smelting

$(Q). PbS + \frac{3}{2}O_2 \xrightarrow{\Delta} PbO + SO_2 \uparrow$ $(2).$ Self reduction

$(R). PbCO_3 \xrightarrow{\Delta} PbO + CO_2 \uparrow$ $(3).$ Calcination

$(S). PbO + C \xrightarrow{\Delta} Pb + CO \uparrow$ $(4).$ Roasting

List-$I$	List-$II$
$(P). PbS + 2PbO \xrightarrow{\Delta} 3Pb + SO_2 \uparrow$	$(1).$ Smelting
$(Q). PbS + \frac{3}{2}O_2 \xrightarrow{\Delta} PbO + SO_2 \uparrow$	$(2).$ Self reduction
$(R). PbCO_3 \xrightarrow{\Delta} PbO + CO_2 \uparrow$	$(3).$ Calcination
$(S). PbO + C \xrightarrow{\Delta} Pb + CO \uparrow$	$(4).$ Roasting