A stream of water flowing horizontally with a | vedclass

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(D) Speed of the water stream,$v = 15\; m s^{-1}$.Cross-sectional area of the tube,$A = 10^{-2}\; m^2$.Volume of water coming out from the pipe per se

Vedclass · Accepted Answer

$2250$

Vedclass · Answer

(D) Speed of the water stream,$v = 15\; m s^{-1}$.Cross-sectional area of the tube,$A = 10^{-2}\; m^2$.Volume of water coming out from the pipe per second,$V = A 	imes v = 10^{-2} 	imes 15 = 0.15\; m^3 s^{-1}$.Density of water,$ho = 10^3\; kg m^{-3}$.Mass of water flowing out through the pipe per second,$\frac{dm}{dt} = ho 	imes V = 10^3 	imes 0.15 = 150\; kg s^{-1}$.The water strikes the wall and does not rebound. Therefore,the force exerted by the water on the wall is given by Newton's second law of motion as:$F = \frac{dp}{dt} = \frac{d(mv)}{dt} = v 	imes \frac{dm}{dt}$.$F = 15\; m s^{-1} 	imes 150\; kg s^{-1} = 2250\; N$.

$A$ stream of water flowing horizontally with a speed of $15\; m s^{-1}$ gushes out of a tube of cross-sectional area $10^{-2}\; m^2$,and hits a vertical wall nearby. What is the force in $N$ exerted on the wall by the impact of water,assuming it does not rebound?

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