$A$ jet of liquid of cross-sectional area $a$ strikes a wall making an angle $\theta$ with the wall. The liquid strikes the wall with velocity $v$ and rebounds elastically. If the density of the liquid is $\rho$,the normal force on the wall is:

Water is flowing at a speed of $1.5\, ms^{-1}$ through a horizontal tube of cross-sectional area $10^{-2}\, m^2$ and you are trying to stop the flow by your palm. Assuming that the water stops immediately after hitting the palm,the minimum force that you must exert should be ......... $N$ (density of water $= 10^3\, kgm^{-3}$)

$A$ pressure-pump has a horizontal tube of cross-sectional area $10 \, cm^{2}$ for the outflow of water at a speed of $20 \, m/s$. The force exerted on the vertical wall just in front of the tube,which stops the water horizontally flowing out of the tube,is $... N$ [Given: density of water $= 1000 \, kg/m^{3}$].

$A$ jet of water with a cross-section of $6 \ cm^2$ strikes a wall at an angle of $60^{\circ}$ to the normal and rebounds elastically from the wall without losing energy. If the velocity of the water in the jet is $12 \ m/s$,the force acting on the wall is ....... $N$.

$A$ tube of length $L = 1 \ m$ is filled completely with an ideal liquid of mass $M_{total} = 2M$,and closed at both ends. The tube is rotated uniformly in a horizontal plane about one of its ends. If the force exerted by the liquid at the other end is $F$,then the angular velocity of the tube is $\sqrt{\frac{F}{\alpha M}}$ in $SI$ units. The value of $\alpha$ is . . . . . . .

Some liquid is filled in a cylindrical vessel of radius $R$. Let $F_1$ be the force applied by the liquid on the bottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section of side $R$. Let $F_2$ be the force applied by the liquid on the bottom of this new vessel. Then: