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(B) In a vertical circular motion with uniform speed $v$,the net centripetal force is provided by the tension $T$ and the component of gravity $mg \co

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minimum at the highest position of the circular path

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(B) In a vertical circular motion with uniform speed $v$,the net centripetal force is provided by the tension $T$ and the component of gravity $mg \cos 	heta$,where $	heta$ is the angle with the vertical.At the highest point,the tension $T_{top}$ is given by $T_{top} + mg = \frac{mv^2}{r}$,so $T_{top} = \frac{mv^2}{r} - mg$.At the lowest point,the tension $T_{bottom}$ is given by $T_{bottom} - mg = \frac{mv^2}{r}$,so $T_{bottom} = \frac{mv^2}{r} + mg$.Since $T_{top} < T_{bottom}$,the tension is minimum at the highest position of the circular path.

$A$ stone of mass $m$,tied to a string,is being whirled in a vertical circle with a uniform speed. The tension in the string is

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