A star is moving towards the earth with a spe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The star is moving towards the Earth,so the observed wavelength will be blue-shifted (decreased).Using the Doppler effect formula for light when t

Vedclass · Accepted Answer

$5802$

Vedclass · Answer

(C) The star is moving towards the Earth,so the observed wavelength will be blue-shifted (decreased).Using the Doppler effect formula for light when the source moves towards the observer:$\lambda' = \lambda \left( 1 - \frac{v}{c} ight)$Given:$\lambda = 5890 \ \mathring A$$v = 4.5 	imes 10^6 \ m/s$$c = 3 	imes 10^8 \ m/s$Substituting the values:$\lambda' = 5890 	imes \left( 1 - \frac{4.5 	imes 10^6}{3 	imes 10^8} ight)$$\lambda' = 5890 	imes \left( 1 - 0.015 ight)$$\lambda' = 5890 	imes 0.985$$\lambda' \approx 5801.65 \ \mathring A \approx 5802 \ \mathring A$Therefore,the correct option is $C$.

$A$ star is moving towards the earth with a speed of $4.5 \times 10^6 \ m/s$. If the true wavelength of a certain line in the spectrum received from the star is $5890 \ \mathring A$,its apparent wavelength will be about........$\mathring A$ $[c = 3 \times 10^8 \ m/s]$

Similar Questions

The wavelength of light from a star is $0.4\%$ more than the corresponding wavelength on the Earth. The velocity of the star with respect to the Earth is:

The apparent wavelength of light from a star moving away from the earth is $0.02 \%$ more than the actual wavelength. The velocity of the star is $[c = 3 \times 10^8 \ m/s]$. (in $km/s$)

$A$ spectral line $\lambda = 5000\ \mathring A$ in the light coming from a distant star is observed as $5200\ \mathring A$. What will be the recession velocity of the star?

The time period of rotation of the sun is $25$ days and its radius is $7 \times 10^8 \ m$. The Doppler shift for the light of wavelength $6000 \ \mathring{A}$ emitted from the surface of the sun will be ...... $\mathring{A}$.

The wavelength of light observed on the earth,from a moving star is found to decrease by $0.05\%$. Relative to the earth,the star is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module