A spectral line lambda = 5000 mathring A in t | vedclass

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(B) The observed wavelength is $\lambda' = 5200\ \mathring A$ and the original wavelength is $\lambda = 5000\ \mathring A$.The Doppler shift in wavele

Vedclass · Accepted Answer

$1.15 	imes 10^7\ m/s$

Vedclass · Answer

(B) The observed wavelength is $\lambda' = 5200\ \mathring A$ and the original wavelength is $\lambda = 5000\ \mathring A$.The Doppler shift in wavelength is $\Delta \lambda = \lambda' - \lambda = 5200\ \mathring A - 5000\ \mathring A = 200\ \mathring A$.According to the Doppler effect for light,the recession velocity $v$ is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $c = 3 	imes 10^8\ m/s$ is the speed of light.Substituting the values: $v = c 	imes \frac{\Delta \lambda}{\lambda} = (3 	imes 10^8\ m/s) 	imes \frac{200\ \mathring A}{5000\ \mathring A}$.$v = 3 	imes 10^8 	imes 0.04 = 0.12 	imes 10^8\ m/s = 1.2 	imes 10^7\ m/s$.Given the options provided,the closest value is $1.15 	imes 10^7\ m/s$.

$A$ spectral line $\lambda = 5000\ \mathring A$ in the light coming from a distant star is observed as $5200\ \mathring A$. What will be the recession velocity of the star?

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