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(D) The induced $emf$ in a conductor moving through a magnetic field is given by $e = Bvl$,where $B$ is the magnetic field,$v$ is the velocity,and $l$

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(D) The induced $emf$ in a conductor moving through a magnetic field is given by $e = Bvl$,where $B$ is the magnetic field,$v$ is the velocity,and $l$ is the length of the side cutting the field lines.Given: $B = 0.6 \, T$,$v = 1 \, cm/s = 0.01 \, m/s$,$l = 5 \, cm = 0.05 \, m$.$1$. From $t = 0$ to $t = 5 \, s$,the loop enters the magnetic field. The induced $emf$ is $e = Bvl = 0.6 	imes 0.01 	imes 0.05 = 3 	imes 10^{-4} \, V$. By Lenz's Law,the direction of the induced current opposes the change in flux,resulting in a negative $emf$ value.$2$. From $t = 5 \, s$ to $t = 15 \, s$,the loop is completely inside the uniform magnetic field. Since the magnetic flux linked with the loop is constant,the induced $emf$ is $e = 0$.$3$. From $t = 15 \, s$ to $t = 20 \, s$,the loop exits the magnetic field. The change in flux is opposite to the entry phase,resulting in an induced $emf$ of $e = +3 	imes 10^{-4} \, V$.Comparing this with the given options,Graph $D$ correctly shows a negative $emf$ during entry,zero $emf$ while inside,and a positive $emf$ during exit.

$A$ square loop of side $5 \, cm$ enters a magnetic field with a velocity of $1 \, cm/s$. The front edge enters the magnetic field at $t = 0$. Which graph best depicts the induced electromotive force $(emf)$ versus time?

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