A square field ABCD of side 90 ,m is so locat | vedclass

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(C) The perimeter of the square field is $4 	imes 90 = 360 \,m$. Initially,Rohan is at $B$ and Rahul is at $C$. The distance between them along the p

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On $AD$ at a distance of $30 \,m$ from $D$

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(C) The perimeter of the square field is $4 	imes 90 = 360 \,m$. Initially,Rohan is at $B$ and Rahul is at $C$. The distance between them along the path (clockwise from $B$ to $C$) is $90 \,m$. Since they move in opposite directions (Rohan clockwise,Rahul anticlockwise),their relative speed is $8 + 10 = 18 \,km/hr$. For the $1st$ meeting,they must cover the initial distance of $90 \,m$. Time taken $t_1 = 90 \,m / 18 \,km/hr = 0.09 \,km / 18 \,km/hr = 0.005 \,hr = 18 \,seconds$. Distance covered by Rohan = $8 \,km/hr 	imes 0.005 \,hr = 0.04 \,km = 40 \,m$. For the $2nd$ meeting,they must cover the total perimeter of $360 \,m$ additionally. Total distance covered by both together = $90 + 360 = 450 \,m$. Time taken for $2nd$ meeting $t_2 = 450 \,m / 18 \,km/hr = 0.45 \,km / 18 \,km/hr = 0.025 \,hr = 90 \,seconds$. Total distance covered by Rohan = $8 \,km/hr 	imes 0.025 \,hr = 0.2 \,km = 200 \,m$. Rohan starts at $B$ and moves clockwise $(B ightarrow C ightarrow D ightarrow A ightarrow B)$. After $200 \,m$: $B$ to $C$ $(90 \,m)$,$C$ to $D$ $(90 \,m)$,$D$ to $A$ $(20 \,m)$. Total distance covered by Rahul = $10 \,km/hr 	imes 0.025 \,hr = 0.25 \,km = 250 \,m$. Rahul starts at $C$ and moves anticlockwise $(C ightarrow B ightarrow A ightarrow D ightarrow C)$. After $250 \,m$: $C$ to $B$ $(90 \,m)$,$B$ to $A$ $(90 \,m)$,$A$ to $D$ $(70 \,m)$. Both are at the same point on $AD$ at a distance of $20 \,m$ from $D$ or $70 \,m$ from $A$. Re-evaluating the meeting point: The relative distance covered for the second meeting is $360 \,m$ after the first meeting. Total distance $450 \,m$. Rohan covers $200 \,m$ from $B$ clockwise,reaching $20 \,m$ past $D$ on $AD$. Rahul covers $250 \,m$ from $C$ anticlockwise,reaching $70 \,m$ past $A$ on $AD$. Both meet at $20 \,m$ from $D$ on $AD$.

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