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(B) Let the starting point be $O$. $1$. Man walks $20 \, m$ East to point $A$. $2$. Turns South and walks $10 \, m$ to point $B$. $3$. Turns West and

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$5$

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(B) Let the starting point be $O$. $1$. Man walks $20 \, m$ East to point $A$. $2$. Turns South and walks $10 \, m$ to point $B$. $3$. Turns West and walks $35 \, m$ to point $C$. $4$. Turns North and walks $5 \, m$ to point $D$. $5$. Turns East and walks $15 \, m$ to point $E$. Let's use a coordinate system where $O = (0, 0)$. - After $20 \, m$ East: $(20, 0)$. - After $10 \, m$ South: $(20, -10)$. - After $35 \, m$ West: $(20 - 35, -10) = (-15, -10)$. - After $5 \, m$ North: $(-15, -10 + 5) = (-15, -5)$. - After $15 \, m$ East: $(-15 + 15, -5) = (0, -5)$. The final position is $(0, -5)$. The initial position is $(0, 0)$. The straight distance is $\sqrt{(0-0)^2 + (-5-0)^2} = \sqrt{25} = 5 \, m$.

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