A spherical ball is dropped in a long column | vedclass

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Question

(B) When a spherical ball is dropped in a highly viscous liquid, it experiences three forces: gravitational force acting downwards, and buoyant force

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$B$

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(B) When a spherical ball is dropped in a highly viscous liquid, it experiences three forces: gravitational force acting downwards, and buoyant force and viscous drag force acting upwards.The net force on the ball is $F_{net} = mg - F_B - F_v$, where $F_v = 6\pi\eta rv$ is the viscous drag force.Initially, the speed $(v)$ is zero, so the viscous drag is zero, and the ball accelerates downwards. As the speed increases, the viscous drag force increases.According to Newton's second law, $ma = mg - F_B - 6\pi\eta rv$. As $v$ increases, the acceleration $a$ decreases.Eventually, the ball reaches a constant terminal velocity when the net force becomes zero $(a = 0)$.This behavior is represented by a curve that starts from the origin, has a decreasing slope (decreasing acceleration), and becomes horizontal (constant velocity) as time increases. Curve $B$ matches this description.

$A$ spherical ball is dropped in a long column of a highly viscous liquid. The curve in the graph shown, which represents the speed of the ball $(v)$ as a function of time $(t)$ is

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