A spherical ball contracts in volume by 0.02 | vedclass

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(C) The Bulk modulus $B$ is defined as the ratio of the change in pressure to the volumetric strain: $B = -\frac{\Delta P}{\Delta V / V}$.Given that t

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$1.01 	imes 10^{10}$

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(C) The Bulk modulus $B$ is defined as the ratio of the change in pressure to the volumetric strain: $B = -\frac{\Delta P}{\Delta V / V}$.Given that the volume contraction is $0.02 \%$,the volumetric strain is $\frac{\Delta V}{V} = -\frac{0.02}{100} = -2 	imes 10^{-4}$.The change in pressure $\Delta P = 50 \, atm = 50 	imes 1.01325 	imes 10^5 \, Pa \approx 50.66 	imes 10^5 \, Pa$.Using the formula $B = \frac{\Delta P}{-(\Delta V / V)} = \frac{50 	imes 1.01325 	imes 10^5}{2 	imes 10^{-4}} = 25 	imes 1.01325 	imes 10^9 = 2.53 	imes 10^{10} \, Nm^{-2}$.However,using the standard approximation $1 \, atm = 1.01 	imes 10^5 \, Pa$ and the provided options,we calculate $B = \frac{50 	imes 1.01 	imes 10^5}{0.02 / 100} = \frac{50.5 	imes 10^5}{2 	imes 10^{-4}} = 25.25 	imes 10^9 = 2.525 	imes 10^{10} \, Nm^{-2}$.Re-evaluating the provided solution logic: If $\frac{\Delta V}{V} = 0.02 \% = 2 	imes 10^{-4}$ and $P = 50 \, atm = 50.5 	imes 10^5 \, Pa$,then $B = \frac{50.5 	imes 10^5}{2 	imes 10^{-4}} = 2.525 	imes 10^{10} \, Nm^{-2}$.Given the options,there is a discrepancy in the provided solution's calculation. Based on standard physics,the closest order of magnitude is $10^{10}$.

$A$ spherical ball contracts in volume by $0.02 \%$,when subjected to a normal uniform pressure of $50$ atmosphere. The Bulk modulus of its material is ............. $Nm^{-2}$.

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