A spherical asteroid having the same density as that of earth is floating in free space. A small pebble is revolving around the asteroid under the influence of gravity near the surface of the asteroid. What is the approximate time period of the pebble?

A satellite revolving around a planet in stationary orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is : (Given $=$ Radius of geo-stationary orbit for earth is $4.2 \times 10^4 \mathrm{~km}$ )

The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to four times the previous value, the new time period will become ......... $hours$

If the earth is at one-fourth of its present distance from the sun, the duration of the year will be

The time period of a satellite revolving around earth in a given orbit is $7 \,hours$. If the radius of orbit is increased to three times its previous value, then approximate new time period of the satellite will be ...... $hours$

The time period of an artificial satellite in a circular orbit of radius $R$ is $2\, days$ and its  orbital velocity is $v_0$. If time period of another satellite in a circular orbit is $16 \,days$ then