$A$ sphere of mass $m$ slides down a smooth inclined plane from a point $B$ at a height of $h$ starting from rest. The magnitude of the change in momentum of the particle between position $A$ (at the bottom of the incline) and $C$ (on the horizontal surface) is (assuming the angle of inclination of the plane is $\theta$ with respect to the horizontal):

  • A
    $0$
  • B
    $2m \sqrt{2gh} \sin \theta$
  • C
    $2m \sqrt{2gh} \sin(\theta/2)$
  • D
    $2m \sqrt{2gh}$

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