A solid cone of height 24 , cm and base radiu | vedclass

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(C) The volume of the solid cone is given by $V_{cone} = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} 	imes \pi 	imes 8^2 	imes 24 = 512 \pi \, cm^3$.Th

Vedclass · Accepted Answer

$57.8$

Vedclass · Answer

(C) The volume of the solid cone is given by $V_{cone} = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} 	imes \pi 	imes 8^2 	imes 24 = 512 \pi \, cm^3$.The volume of the solid cylinder formed is $V_{cylinder} = \pi r_2^2 h_2 = \pi 	imes 6^2 	imes 6 = 216 \pi \, cm^3$.The volume of material wasted is $V_{wasted} = V_{cone} - V_{cylinder} = 512 \pi - 216 \pi = 296 \pi \, cm^3$.The percentage of material wasted is $\frac{V_{wasted}}{V_{cone}} 	imes 100 = \frac{296 \pi}{512 \pi} 	imes 100 = \frac{296}{512} 	imes 100 = 57.8125 \% \approx 57.8 \%$.

$A$ solid cone of height $24 \, cm$ and base radius $8 \, cm$ is melted to form a solid cylinder of radius $6 \, cm$ and height $6 \, cm$. In the whole process,what percent of material is wasted (in $\%$)?

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