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(C) Given: Initial velocity $u = 0$. Let the constant acceleration be $a$.For the first time interval $t$,the distance travelled is $s_1 = 10 \, m$.Us

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$30$

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(C) Given: Initial velocity $u = 0$. Let the constant acceleration be $a$.For the first time interval $t$,the distance travelled is $s_1 = 10 \, m$.Using the equation of motion $s = ut + \frac{1}{2}at^2$:$10 = 0(t) + \frac{1}{2}at^2 \implies 10 = \frac{1}{2}at^2$  --- (Equation $1$)For the total time interval $2t$,let the total distance travelled be $s_2 = 10 + x$,where $x$ is the distance travelled in the next $t \, s$.$10 + x = 0(2t) + \frac{1}{2}a(2t)^2$$10 + x = \frac{1}{2}a(4t^2) = 4 \left( \frac{1}{2}at^2 \right)$ --- (Equation $2$)Substituting Equation $1$ into Equation $2$:$10 + x = 4(10)$$10 + x = 40$$x = 30 \, m$.

$A$ small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of $10 \, m$ in $t \, s$,the distance travelled by the toy in the next $t \, s$ will be ......... $m$.

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