$A$ small child tries to move a large rubber toy placed on the ground. The toy does not move but gets deformed under her pushing force $F$,which is obliquely upward as shown in the figure. Then,

  • A
    the resultant of the pushing force $F$,weight of the toy,normal force by the ground on the toy and the frictional force is zero
  • B
    the normal force by the ground is equal and opposite to the weight of the toy
  • C
    the pushing force $F$ of the child is balanced by the equal and opposite frictional force
  • D
    the pushing force $F$ of the child is balanced by the total internal force in the toy generated due to deformation

Explore More

Similar Questions

$A$ uniform sphere of weight $W$ and radius $R = 3\,m$ is held by a string of length $L = 2\,m$ attached to a frictionless wall as shown in the figure. The tension in the string is:

Difficult
View Solution

$A$ body is moving under the action of two forces $\vec{F}_1 = 2\hat{i} - 5\hat{j}$ and $\vec{F}_2 = 3\hat{i} - 4\hat{j}$. Its velocity will become uniform under an additional third force $\vec{F}_3$ given by:

Define mechanical advantage in a lever.

$A$ mass $M \text{ kg}$ is suspended by a weightless string. The horizontal force required to hold the mass at $60^{\circ}$ with the vertical is

Can a stationary object remain stationary if multiple external forces act upon it?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo