(C) The wave velocity $V$ is given by $V = f\lambda$,where $f$ is the frequency.The maximum particle velocity $v$ for a sine wave is given by $v = A\o

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$V = v$ if $A = \frac{\lambda}{2\pi}$

(C) The wave velocity $V$ is given by $V = f\lambda$,where $f$ is the frequency.The maximum particle velocity $v$ for a sine wave is given by $v = A\omega$,where $\omega = 2\pi f$ is the angular frequency.Equating the two velocities: $V = v$$f\lambda = A(2\pi f)$Dividing both sides by $f$ (assuming $f \neq 0$):$\lambda = 2\pi A$Rearranging for $A$:$A = \frac{\lambda}{2\pi}$Thus,the correct condition is $A = \frac{\lambda}{2\pi}$.

Class 11 Physics Waves and Sound Wave Equation and Characteristics of Waves

Easy

$A$ sine wave has an amplitude $A$ and wavelength $\lambda$. Let $V$ be the wave velocity and $v$ be the maximum velocity of a particle in the medium. Then:

A
$V = v$ if $\lambda = \frac{3A}{2\pi}$
B
$V = v$ if $A = 2\pi\lambda$
C
$V = v$ if $A = \frac{\lambda}{2\pi}$
D
$V$ can not be equal to $v$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Waves and Sound

Subtopic

Wave Equation and Characteristics of Waves

For a wave equation $y = 8 \sin 2\pi (0.1x - 2t) \, cm$,find the phase difference in $^\circ$ between two particles separated by a distance of $2 \, cm$.

Difficult

View Solution

$A$ transverse wave of amplitude $0.5\, m$,wavelength $1\, m$,and frequency $2\, Hz$ is propagating in a string in the negative $x$-direction. The expression for this wave is:

EasyAIIMS 1980

View Solution

The equation $y = A \cos^2 \left( 2\pi nt - 2\pi \frac{x}{\lambda} \right)$ represents a wave with

Medium

View Solution

The equation of a progressive wave is $y = 4 \sin(4 \pi t - 0.04 x + \pi / 3)$,where $x$ is in meters and $t$ is in seconds. The velocity of the wave is:

EasyWBJEE 2010

View Solution

$A$ wave is given by $y=5 \times 10^{-3} \sin \left(12.5 \pi x - \frac{\pi}{2} t\right)$. Then its wavelength and time period are respectively ($y$ and $x$ are in metres and $t$ is in seconds).

DifficultTS EAMCET 2023

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ sine wave has an amplitude $A$ and wavelength $\lambda$. Let $V$ be the wave velocity and $v$ be the maximum velocity of a particle in the medium. Then:

Similar Questions

For a wave equation $y = 8 \sin 2\pi (0.1x - 2t) \, cm$,find the phase difference in $^\circ$ between two particles separated by a distance of $2 \, cm$.

$A$ transverse wave of amplitude $0.5\, m$,wavelength $1\, m$,and frequency $2\, Hz$ is propagating in a string in the negative $x$-direction. The expression for this wave is:

The equation $y = A \cos^2 \left( 2\pi nt - 2\pi \frac{x}{\lambda} \right)$ represents a wave with

The equation of a progressive wave is $y = 4 \sin(4 \pi t - 0.04 x + \pi / 3)$,where $x$ is in meters and $t$ is in seconds. The velocity of the wave is:

$A$ wave is given by $y=5 \times 10^{-3} \sin \left(12.5 \pi x - \frac{\pi}{2} t\right)$. Then its wavelength and time period are respectively ($y$ and $x$ are in metres and $t$ is in seconds).

Vedclass Test Series

Exam Paper Generator

Online Exam Module