A simple magnifying lens is used in such a wa | vedclass

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(C) For a simple magnifying lens,the magnification $m$ when the image is formed at the near point $D$ is given by the formula:$m = 1 + \frac{D}{f}$Giv

Vedclass · Accepted Answer

$25 \, mm$

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(C) For a simple magnifying lens,the magnification $m$ when the image is formed at the near point $D$ is given by the formula:$m = 1 + \frac{D}{f}$Given that the magnification $m = 10$ and the near point $D = 25 \, cm = 250 \, mm$.Substituting these values into the formula:$10 = 1 + \frac{25 \, cm}{f}$$9 = \frac{25 \, cm}{f}$$f = \frac{25}{9} \, cm \approx 2.77 \, cm = 27.7 \, mm$.However,checking the options provided,if we assume the standard approximation $m \approx \frac{D}{f}$ (for large magnification),then $10 = \frac{25 \, cm}{f}$,which gives $f = 2.5 \, cm = 25 \, mm$. Thus,option $C$ is the intended answer.

$A$ simple magnifying lens is used in such a way that an image is formed at $25 \, cm$ away from the eye. In order to have $10$ times magnification,the focal length of the lens should be

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