A sealed flask with a capacity of 2 , dm^{3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Calculate the number of moles of propane $(C_{3}H_{8})$: Molar mass of $C_{3}H_{8} = (3 	imes 12) + (8 	imes 1) = 44 \, g \, mol^{-1}$. Mol

Vedclass · Accepted Answer

$1655$

Vedclass · Answer

(C) $1$. Calculate the number of moles of propane $(C_{3}H_{8})$: Molar mass of $C_{3}H_{8} = (3 	imes 12) + (8 	imes 1) = 44 \, g \, mol^{-1}$. Moles $(n)$ = $\frac{11 \, g}{44 \, g \, mol^{-1}} = 0.25 \, mol$. $2$. Use the ideal gas equation $PV = nRT$: Given $P = 2 \, MPa = 2 	imes 10^{6} \, Pa$,$V = 2 \, dm^{3} = 2 	imes 10^{-3} \, m^{3}$,$n = 0.25 \, mol$,$R = 8.3 \, J \, K^{-1} \, mol^{-1}$. $2 	imes 10^{6} 	imes 2 	imes 10^{-3} = 0.25 	imes 8.3 	imes T$. $4000 = 2.075 	imes T$. $T = \frac{4000}{2.075} \approx 1927.71 \, K$. $3$. Convert temperature to Celsius: $T(^{\circ}C) = T(K) - 273.15 = 1927.71 - 273.15 = 1654.56 \, ^{\circ}C$. Rounding to the nearest integer,we get $1655 \, ^{\circ}C$.

Similar Questions

The same gas is filled in two containers $X$ and $Y$. If the pressure,volume,and absolute temperature of the gas in container $X$ are three times those in container $Y$,and the mass of the gas in $X$ is $m \, g$,what will be the mass of the gas in $Y$?

The following $P$ vs $V$ curve is plotted. What is the relation between $T_1$,$T_2$ and $T_3$?

If $2 \, \text{moles}$ of an ideal gas occupy a volume of $44.8 \, L$ at a temperature of $546 \, K$,what will be the pressure in $atm$?

The volume versus temperature graph of $1 \ mole$ of an ideal gas is given below. The pressure of the gas (in $atm$) at $X, Y$ and $Z$,respectively,are

$A$ gas obeys Charles's law in the temperature range $0-500 \ K$ at a given pressure. Its volume changes to zero at a temperature of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module