A satellite is moving around the earth with s | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{v}=\sqrt{\frac{\mathrm{GM}}{\mathrm{r}}}, \quad \mathrm{v} \propto \frac{1}{\sqrt{\mathrm{r}}}$

$100 	imes \frac{\Delta \mathrm{v}}{\math

Vedclass · Accepted Answer

Increase by $1\%$

Vedclass · Answer

$\mathrm{v}=\sqrt{\frac{\mathrm{GM}}{\mathrm{r}}}, \quad \mathrm{v} \propto \frac{1}{\sqrt{\mathrm{r}}}$

$100 	imes \frac{\Delta \mathrm{v}}{\mathrm{v}}=-\frac{1}{2} \frac{\Delta \mathrm{r}}{\mathrm{r}} 	imes 100$

increased by $1 \%$

A satellite is moving around the earth with speed $V$ in circular orbit of radius $r$ . If the orbital radius is decreased by $2\%$ , the speed of the satellite will

Similar Questions

Which of the following graph represents the variations of acceleration due to gravity $(g)$ with distance $r$ from the centre of earth?

Which graph correctly presents the variation of acceleration due to gravity with the distance from the centre of the earth (radius of the earth $= R_E$ )?

The weight of a body on the surface of the earth is $63\, N$. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth ? (in $N$)

Gravitation is the phenomenon of interaction between ............

A spherical planet far out in space has a mass ${M_0}$ and diameter ${D_0}$. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to