$A$ sample of a liquid has an initial volume of $1.5\,L$. The volume is reduced by $0.2\,mL$ when the pressure increases by $140\,kPa$. What is the bulk modulus of the liquid?

  • A
    $3.05 \times 10^9\,Pa$
  • B
    $1.05 \times 10^9\,Pa$
  • C
    $1.05 \times 10^7\,Pa$
  • D
    $1.05 \times 10^{11}\,Pa$

Explore More

Similar Questions

$A$ solid sphere of radius $r$ made of a soft material of bulk modulus $K$ is surrounded by a liquid in a cylindrical container. $A$ massless piston of area $a$ floats on the surface of the liquid,covering the entire cross-section of the cylindrical container. When a mass $m$ is placed on the surface of the piston to compress the liquid,the fractional decrement in the radius of the sphere,$\left( \frac{dr}{r} \right)$ is:

If a rubber ball is taken to a depth of $200 \ m$ in a pool,its volume decreases by $0.1 \%$. If the density of the water is $1 \times 10^3 \ kg/m^3$ and $g = 10 \ m/s^2$,then the bulk modulus (volume elasticity) in $N/m^2$ will be:

Difficult
View Solution

To what depth must a rubber ball be taken in deep sea so that its volume is decreased by $0.1\,\%$. (The bulk modulus of rubber is $9.8 \times 10^8 \, N/m^2$ and the density of sea water is $10^3 \, kg/m^3$.) (in $, m$)

How much should the pressure on a litre of water be changed to compress it by $0.10\%?$

If a brass sphere of radius $36 \ cm$ is submerged in a lake at a depth where the pressure is $10^7 \ Pa$,then the change in the radius of the sphere is $($Bulk modulus of brass $= 60 \ GPa)$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo