A running track is in the shape of a circular | vedclass

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Question

For the running track in the shape of a circular ring, let the inner radius be $r_{1} \,m$ and the outer radius be $r_{2} \,m$.

Difference of

Vedclass · Accepted Answer

$7$

Vedclass · Answer

For the running track in the shape of a circular ring, let the inner radius be $r_{1} \,m$ and the outer radius be $r_{2} \,m$.

Difference of circumferences $=44 \,m$

$	herefore 2 \pi r_{2}-2 \pi r_{1}=44$

$	herefore 2 \pi\left(r_{2}-r_{1}ight)=44$

$	herefore 2 	imes \frac{22}{7}\left(r_{2}-r_{1}ight)=44$

$	herefore r_{2}-r_{1}=\frac{44 	imes 7}{2 	imes 22}$

$	herefore r_{2}-r_{1}=7 \,m$

$	herefore$ The width of the track $=7\,m$

A running track is in the shape of a circular ring. The difference of its outer circumference and inner circumference is $44\,m .$ Then, the width of the track is $\ldots \ldots \ldots \ldots$$m$.

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