A running track is in the shape of a circular | vedclass

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(B) For the running track in the shape of a circular ring,let the inner radius be $r_{1} \,m$ and the outer radius be $r_{2} \,m$.Difference of circum

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) For the running track in the shape of a circular ring,let the inner radius be $r_{1} \,m$ and the outer radius be $r_{2} \,m$.Difference of circumferences $= 44 \,m$$	herefore 2 \pi r_{2} - 2 \pi r_{1} = 44$$	herefore 2 \pi (r_{2} - r_{1}) = 44$$	herefore 2 	imes \frac{22}{7} (r_{2} - r_{1}) = 44$$	herefore r_{2} - r_{1} = \frac{44 	imes 7}{2 	imes 22}$$	herefore r_{2} - r_{1} = 7 \,m$$	herefore$ The width of the track $= 7 \,m$.

$A$ running track is in the shape of a circular ring. The difference of its outer circumference and inner circumference is $44\,m$. Then,the width of the track is $\ldots \ldots \ldots \ldots\,m$.

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