A rubber cord 10, m long is suspended vertica | vedclass

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(A) The elongation $\Delta L$ of a rod of length $L$,density $d$,and Young's modulus $Y$ due to its own weight is given by the formula: $\Delta L = \f

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$15 	imes 10^{-4}\, m$

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(A) The elongation $\Delta L$ of a rod of length $L$,density $d$,and Young's modulus $Y$ due to its own weight is given by the formula: $\Delta L = \frac{L^2 dg}{2Y}$.Given values are: $L = 10\, m$,$d = 1500\, kg/m^3$,$Y = 5 	imes 10^8\, N/m^2$,and $g = 10\, m/s^2$.Substituting these values into the formula:$\Delta L = \frac{(10)^2 	imes 1500 	imes 10}{2 	imes 5 	imes 10^8}$$\Delta L = \frac{100 	imes 15000}{10 	imes 10^8}$$\Delta L = \frac{1500000}{10^9} = 15 	imes 10^5 	imes 10^{-9} = 15 	imes 10^{-4}\, m$.

$A$ rubber cord $10\, m$ long is suspended vertically. How much does it stretch under its own weight? (Density of rubber is $1500\, kg/m^3$,$Y = 5 \times 10^8\, N/m^2$,$g = 10\, m/s^2$)

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