A road is 10,m wide. Its radius of curvature | vedclass

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(D) The banking angle $	heta$ is given by $	an 	heta = \frac{h}{w}$,where $h = 1.5\,m$ is the height difference and $w = 10\,m$ is the width of the

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(D) The banking angle $	heta$ is given by $	an 	heta = \frac{h}{w}$,where $h = 1.5\,m$ is the height difference and $w = 10\,m$ is the width of the road.$	an 	heta = \frac{1.5}{10} = 0.15$.For a banked road,the optimum velocity $v$ is given by the formula $v = \sqrt{rg 	an 	heta}$,where $r = 50\,m$ is the radius of curvature and $g = 9.8\,m/s^2$ is the acceleration due to gravity.Substituting the values: $v = \sqrt{50 	imes 9.8 	imes 0.15}$.$v = \sqrt{490 	imes 0.15} = \sqrt{73.5} \approx 8.57\,m/s$.Rounding to the nearest given option,the velocity is $8.5\,m/s$.

$A$ road is $10\,m$ wide. Its radius of curvature is $50\,m$. The outer edge is raised above the inner edge by a distance of $1.5\,m$. This road is most suited for a velocity of ......... $m/s$. (in $.5$)

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