$A$ ring of mass $M$ and radius $R$ is rotating about its axis with angular velocity $\omega$. Two identical bodies each of mass $m$ are now gently attached at the two ends of a diameter of the ring. Because of this,the kinetic energy loss will be

  • A
    $\frac{m(M + 2m)}{M} \omega^2 R^2$
  • B
    $\frac{Mm}{(M + m)} \omega^2 R^2$
  • C
    $\frac{Mm}{(M + 2m)} \omega^2 R^2$
  • D
    $\frac{(M + m)M}{(M + 2m)} \omega^2 R^2$

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