A rigid nitrogen tank stored inside a laborat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Since the tank is rigid, the volume $V$ remains constant. According to Gay-Lussac's Law, for a fixed amount of gas at constant volume, the pressur

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(A) Since the tank is rigid, the volume $V$ remains constant. According to Gay-Lussac's Law, for a fixed amount of gas at constant volume, the pressure is directly proportional to the absolute temperature: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.Given:$P_1 = 30 \ atm$$T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$$T_2 = 45^{\circ} C = 45 + 273 = 318 \ K$Substituting the values into the equation:$\frac{30}{300} = \frac{P_2}{318}$$0.1 = \frac{P_2}{318}$$P_2 = 0.1 	imes 318 = 31.8 \ atm$.Rounding to the nearest integer, we get $P_2 = 32 \ atm$.

$A$ rigid nitrogen tank stored inside a laboratory has a pressure of $30 \ atm$ at $06:00 \ am$ when the temperature is $27^{\circ} C$. At $03:00 \ pm$, when the temperature is $45^{\circ} C$, the pressure in the tank will be $...... \ atm.$ [nearest integer]

Similar Questions

$n$ moles of an ideal gas at temperature $T$ (in kelvin) occupy $V \ L$ of volume,exerting a pressure of $P$ atmospheres. What is the concentration (in $mol / L$)?

What is the effect of temperature change on the Boyle's law isotherm graph?

For an ideal gas,the compressibility factor $(Z)$ is

What is the density of $SO_2$ gas at $27\,^oC$ temperature and $2\, atm$ pressure in $g/L$? (Atomic weights: $S = 32, O = 16, R = 0.082\, L\, atm\, K^{-1}\, mol^{-1}$)

An ideal gas expands isothermally and reversibly from $10 \ m^{3}$ to $20 \ m^{3}$ at $300 \ K$ performing $5.187 \ kJ$ of work on surroundings. Calculate the number of moles of gas undergoing expansion? $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module