A rectangular piece of paper is 22 text{ cm} | vedclass

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(B) When the paper is rolled along its length,the length of the paper becomes the circumference of the base of the cylinder,and the width of the paper

Vedclass · Accepted Answer

$385 	ext{ cm}^3$

Vedclass · Answer

(B) When the paper is rolled along its length,the length of the paper becomes the circumference of the base of the cylinder,and the width of the paper becomes the height of the cylinder.Given: Circumference $(2 \pi r) = 22 	ext{ cm}$ and height $(h) = 10 	ext{ cm}$.From $2 \pi r = 22$,we have $2 	imes \frac{22}{7} 	imes r = 22$,which gives $r = \frac{7}{2} 	ext{ cm}$.The volume of the cylinder $(V)$ is given by the formula $V = \pi r^2 h$.Substituting the values: $V = \frac{22}{7} 	imes (\frac{7}{2})^2 	imes 10$.$V = \frac{22}{7} 	imes \frac{49}{4} 	imes 10 = 22 	imes \frac{7}{4} 	imes 10 = 11 	imes 7 	imes 5 = 385 	ext{ cm}^3$.

$A$ rectangular piece of paper is $22 \text{ cm}$ long and $10 \text{ cm}$ wide. $A$ cylinder is formed by rolling the paper along its length. The volume of the cylinder is

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