A rectangular loop with a sliding connector o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The motional electromotive force (emf) induced in the sliding connector is given by $e = Bvl$. Substituting the given values: $e = 2 	imes 2

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) $1$. The motional electromotive force (emf) induced in the sliding connector is given by $e = Bvl$. Substituting the given values: $e = 2 	imes 2 	imes 1 = 4 \, V$.$2$. The connector acts as a battery of emf $E = 4 \, V$ and internal resistance $r = 2 \, \Omega$.$3$. The two resistors of $6 \, \Omega$ and $3 \, \Omega$ are connected in parallel. Their equivalent resistance $R_{eq}$ is given by $\frac{1}{R_{eq}} = \frac{1}{6} + \frac{1}{3} = \frac{1+2}{6} = \frac{3}{6} = \frac{1}{2}$,so $R_{eq} = 2 \, \Omega$.$4$. The total resistance of the circuit is $R_{total} = R_{eq} + r = 2 \, \Omega + 2 \, \Omega = 4 \, \Omega$.$5$. The current $i$ flowing through the connector is $i = \frac{e}{R_{total}} = \frac{4 \, V}{4 \, \Omega} = 1 \, A$.$6$. The magnetic force acting on the connector is $F_m = Bil$. Substituting the values: $F_m = 2 \, T 	imes 1 \, A 	imes 1 \, m = 2 \, N$.$7$. To maintain a constant velocity,the external force $F_{ext}$ must be equal and opposite to the magnetic force $F_m$. Therefore,$F_{ext} = F_m = 2 \, N$.

Similar Questions

$A$ conducting rod is moving towards the right with a velocity '$V$' in a uniform magnetic field '$B$'. If the direction of the induced current '$i$' is as shown in the figure,then the direction of '$B$' is:

$A$ rod of length $2 \, m$ slides with a speed of $5 \, ms^{-1}$ on a rectangular conducting frame as shown in the figure. There exists a uniform magnetic field of $0.04 \, T$ perpendicular to the plane of the figure. If the resistance of the rod is $3 \, \Omega$, the current through the rod is

Vedclass Test Series

Exam Paper Generator

Online Exam Module