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(B) The deviation $\delta$ produced by two plane mirrors inclined at an angle $	heta$ is given by the formula $\delta = 360^o - 2	heta$.Given that t

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$11$

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(B) The deviation $\delta$ produced by two plane mirrors inclined at an angle $	heta$ is given by the formula $\delta = 360^o - 2	heta$.Given that the deviation $\delta = 300^o$,we have $300^o = 360^o - 2	heta$.Solving for $	heta$,we get $2	heta = 60^o$,which implies $	heta = 30^o$.The number of images $n$ formed by two mirrors inclined at an angle $	heta$ is given by $n = \frac{360^o}{	heta} - 1$.Substituting $	heta = 30^o$,we get $n = \frac{360^o}{30^o} - 1 = 12 - 1 = 11$.Therefore,the number of observable images is $11$.

$A$ ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $300^o$. The number of observable images is:

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