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(B) According to Snell's Law,the refractive index $\mu$ of the medium with respect to air is given by $\mu = \frac{\sin i}{\sin r}$.Also,the refractiv

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$2.12 	imes 10^8 \ m/s$

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(B) According to Snell's Law,the refractive index $\mu$ of the medium with respect to air is given by $\mu = \frac{\sin i}{\sin r}$.Also,the refractive index is related to the velocity of light in vacuum $(c)$ and in the medium $(v)$ by $\mu = \frac{c}{v}$.Equating these,we get $\frac{c}{v} = \frac{\sin i}{\sin r}$.Given $i = 45^\circ$,$r = 30^\circ$,and $c = 3 	imes 10^8 \ m/s$.Substituting the values: $\frac{3 	imes 10^8}{v} = \frac{\sin 45^\circ}{\sin 30^\circ} = \frac{1/\sqrt{2}}{1/2} = \sqrt{2}$.Therefore,$v = \frac{3 	imes 10^8}{\sqrt{2}} \approx \frac{3 	imes 10^8}{1.414} \approx 2.12 	imes 10^8 \ m/s$.

$A$ ray of light is incident on the surface of separation of a medium at an angle of $45^\circ$ and is refracted in the medium at an angle of $30^\circ$. What will be the velocity of light in the medium?

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