(A) The half-life period $(t_{1/2})$ of the radioactive decay is given as $6.93 \ min$.For a first-order reaction,the rate constant $(k)$ is calculate

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(A) The half-life period $(t_{1/2})$ of the radioactive decay is given as $6.93 \ min$.For a first-order reaction,the rate constant $(k)$ is calculated using the formula: $k = \frac{0.693}{t_{1/2}}$.Substituting the given value: $k = \frac{0.693}{6.93} = 0.10 \ \min^{-1}$.

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Medium

$A$ radioactive sample decays to half of its initial concentration in $6.93 \ min$. It further decays half in next $6.93 \ min$. The rate constant for the reaction is ..... $\min^{-1}$

A
$0.10$
B
$0.01$
C
$1.0$
D
$0.001$

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Rate of decay and Half-life

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$A$ radioactive sample decays to half of its initial concentration in $6.93 \ min$. It further decays half in next $6.93 \ min$. The rate constant for the reaction is ..... $\min^{-1}$

Similar Questions

$^{14}C$ has a half-life of $5760 \ years$. $100 \ mg$ of a sample containing $^{14}C$ is reduced to $25 \ mg$ in ......... $years$.

For $Ra^{226}$,the $t_{1/2}$ is $1620 \ years$. From $0.001 \ g$ of $Ra$,how many $\alpha$-particles are released per $min$?

The half-life of radium-$226$ is $1620$ years. The time taken to convert $10 \ g$ of radium to $1.25 \ g$ is ......... years.

The half-life of ${}^{65}Zn$ is $245 \ days$. After $x$ days,$75\%$ of original activity remained. The value of $x$ in days is . . . . . . . (Nearest integer)(Given $: \log 3=0.4771$ and $\log 2=0.3010$ )

$A$ radioactive isotope decays at such a rate that after $96 \ min$,only $\frac{1}{8}$ of the original amount remains. The half-life of this nuclide in minutes is:

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The half-life of ${}^{65}Zn$ is $245 \ days$. After $x$ days,$75\%$ of original activity remained. The value of $x$ in days is . . . . . . . (Nearest integer)
(Given $: \log 3=0.4771$ and $\log 2=0.3010$ )