$A$ radio can tune in to any station in the $7.5\; MHz$ to $12\; MHz$ band. What is the corresponding wavelength band?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The radio tunes to a minimum frequency of $v_{1} = 7.5\; MHz = 7.5 \times 10^{6}\; Hz$.
The maximum frequency is $v_{2} = 12\; MHz = 12 \times 10^{6}\; Hz$.
The speed of light is $c = 3 \times 10^{8}\; m/s$.
The wavelength $\lambda$ is related to frequency $v$ by the formula $\lambda = \frac{c}{v}$.
For the minimum frequency $v_{1}$,the maximum wavelength $\lambda_{1}$ is:
$\lambda_{1} = \frac{c}{v_{1}} = \frac{3 \times 10^{8}}{7.5 \times 10^{6}} = 40\; m$.
For the maximum frequency $v_{2}$,the minimum wavelength $\lambda_{2}$ is:
$\lambda_{2} = \frac{c}{v_{2}} = \frac{3 \times 10^{8}}{12 \times 10^{6}} = 25\; m$.
Thus,the corresponding wavelength band is $25\; m$ to $40\; m$.

Explore More

Similar Questions

What is the range of frequency of $EM$ waves that are reflected back by the ionosphere?

An electromagnetic wave travelling in $x$-direction is described by field equation $E_y = 300 \sin \omega \left( t - \frac{x}{c} \right)$. If the electron is restricted to move in $y$-direction only with speed of $1.5 \times 10^6 \text{ m/s}$,then the ratio of maximum electric and magnetic forces acting on the electron is . . . . . . .

The speed of an electromagnetic wave in a vacuum depends upon the source of radiation.

Electromagnetic waves with frequencies ranging from $2\,\text{MHz}$ to $30\,\text{MHz}$ are propagated by:

The oscillating electric and magnetic vectors of an electromagnetic wave are oriented along

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo