(N/A) The radio tunes to a minimum frequency of $v_{1} = 7.5\; MHz = 7.5 \times 10^{6}\; Hz$.
The maximum frequency is $v_{2} = 12\; MHz = 12 \times 10^{6}\; Hz$.
The speed of light is $c = 3 \times 10^{8}\; m/s$.
The wavelength $\lambda$ is related to frequency $v$ by the formula $\lambda = \frac{c}{v}$.
For the minimum frequency $v_{1}$,the maximum wavelength $\lambda_{1}$ is:
$\lambda_{1} = \frac{c}{v_{1}} = \frac{3 \times 10^{8}}{7.5 \times 10^{6}} = 40\; m$.
For the maximum frequency $v_{2}$,the minimum wavelength $\lambda_{2}$ is:
$\lambda_{2} = \frac{c}{v_{2}} = \frac{3 \times 10^{8}}{12 \times 10^{6}} = 25\; m$.
Thus,the corresponding wavelength band is $25\; m$ to $40\; m$.