An electromagnetic wave travelling in x-direc | vedclass

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(A) The electric force on the electron is given by $F_e = eE$,where $e$ is the charge of the electron and $E$ is the electric field amplitude.The magn

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(A) The electric force on the electron is given by $F_e = eE$,where $e$ is the charge of the electron and $E$ is the electric field amplitude.The magnetic force on the electron is given by $F_m = evB$,where $v$ is the speed of the electron and $B$ is the magnetic field amplitude.For an electromagnetic wave,the relationship between the amplitudes of electric and magnetic fields is $E = cB$,where $c$ is the speed of light $(c = 3 	imes 10^8 	ext{ m/s})$.Therefore,the ratio of maximum forces is $\frac{F_e}{F_m} = \frac{eE}{evB} = \frac{E}{v(E/c)} = \frac{c}{v}$.Given $c = 3 	imes 10^8 	ext{ m/s}$ and $v = 1.5 	imes 10^6 	ext{ m/s}$,the ratio is $\frac{3 	imes 10^8}{1.5 	imes 10^6} = \frac{300 	imes 10^6}{1.5 	imes 10^6} = 200$.

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