A quantity of aluminium has a mass of 54.0 g | vedclass

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(C) Step $1$: Calculate the number of moles of $Al$ atoms.$n(Al) = \frac{	ext{mass of } Al}{	ext{molar mass of } Al} = \frac{54.0 \ g}{27.0 \ g/mol}

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(C) Step $1$: Calculate the number of moles of $Al$ atoms.$n(Al) = \frac{	ext{mass of } Al}{	ext{molar mass of } Al} = \frac{54.0 \ g}{27.0 \ g/mol} = 2.0 \ mol$.Step $2$: Since the number of atoms is the same,the number of moles of $Mg$ atoms must also be $2.0 \ mol$.Step $3$: Calculate the mass of $Mg$ atoms.$	ext{mass of } Mg = n(Mg) 	imes 	ext{molar mass of } Mg = 2.0 \ mol 	imes 24.0 \ g/mol = 48.0 \ g$.

$A$ quantity of aluminium has a mass of $54.0 \ g$. What is the mass of the same number of magnesium atoms? ........... $g$

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