One mole of oxygen gas at STP is equal to | vedclass

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(A) $1$ mole of $O_{2(g)}$ at $STP$ contains Avogadro number $(N_A = 6.022 	imes 10^{23} \ mol^{-1})$ of $O_2$ molecules.Since $1$ mole of $O_2$ has

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$6.022 	imes 10^{23}$ molecules of oxygen

Vedclass · Answer

(A) $1$ mole of $O_{2(g)}$ at $STP$ contains Avogadro number $(N_A = 6.022 	imes 10^{23} \ mol^{-1})$ of $O_2$ molecules.Since $1$ mole of $O_2$ has a molar mass of $32 \ g/mol$,it corresponds to $32 \ g$ of oxygen gas.Therefore,the correct statement is that it contains $6.022 	imes 10^{23}$ molecules of oxygen.

One mole of oxygen gas at $STP$ is equal to

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