$A$ pure breeding pea plant with the dominant phenotype of character $A$ and recessive phenotype of character $B$ was crossed with another pure breeding plant with the recessive phenotype of $A$ and dominant phenotype of character $B$. An offspring of this cross was crossed with a homozygous recessive for both the characters $A$ and $B$. The following results were obtained:
$22$ were phenotypically dominant for $A$ and recessive for $B$.
$4$ were phenotypically dominant for both $A$ and $B$.
$4$ were phenotypically recessive for both $A$ and $B$.
$24$ were phenotypically recessive for $A$ and dominant for $B$.
These results show that:

  • A
    Genes $A$ and $B$ are linked
  • B
    Independent segregation of genes $A$ and $B$
  • C
    Mendelian dihybrid inheritance
  • D
    Polygenic inheritance

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Similar Questions

Why did Morgan choose the fruit fly for his experiments to prove the chromosomal theory of inheritance?

Select the correct statement from the ones given below with respect to dihybrid cross.

Which of the following statements is $NOT$ true for two genes showing $50\%$ recombination frequency?

$A$ test cross of an $F_1$ fly $+a/+b$ produces the following offspring:
$++/ab = 9$
$ab/ab = 9$
$+b/ab = 41$
$a+/ab = 41$
What is the distance between the linked genes?

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Who used the frequency of recombination as a measure of the distance between genes on a chromosome and mapped their position?

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