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Question

(A) Let the side length of the square park be $l$. The area of a square is given by $A = l^2$.Given $A = 100 \; m^2$,we have $l = \sqrt{100} = 10 \; m

Vedclass · Accepted Answer

$(10 \pm 0.01)$

Vedclass · Answer

(A) Let the side length of the square park be $l$. The area of a square is given by $A = l^2$.Given $A = 100 \; m^2$,we have $l = \sqrt{100} = 10 \; m$.The relative error in area is related to the relative error in length by the formula $\frac{\Delta A}{A} = 2 \frac{\Delta l}{l}$.Substituting the given values,$\frac{0.2}{100} = 2 \frac{\Delta l}{10}$.Solving for $\Delta l$: $\Delta l = \frac{0.2 	imes 10}{100 	imes 2} = \frac{2}{200} = 0.01 \; m$.Thus,the side of the park is $(10 \pm 0.01) \; m$.

$A$ public park,in the form of a square,has an area of $(100 \pm 0.2) \; m^2$. The side of the park is ............ $m$.

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