A projectile is given an initial velocity of | vedclass

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Question

$\mathrm{ucos} 	heta=1$

$usin$ $	heta=2$

$\Rightarrow 	an 	heta=2, \mathrm{u}=\sqrt{5}$

equation of trajectory $y=x 	an 	heta-\frac{1}{

Vedclass · Accepted Answer

$y =2 x -5x^2$

Vedclass · Answer

$\mathrm{ucos} 	heta=1$

$usin$ $	heta=2$

$\Rightarrow 	an 	heta=2, \mathrm{u}=\sqrt{5}$

equation of trajectory $y=x 	an 	heta-\frac{1}{2} g\left(\frac{x}{u \cos 	heta}ight)^{2}$

$y=x 	imes 2-\frac{1}{2} 	imes 10 	imes\left(\frac{x}{1}ight)^{2}$

$y=2 x-5 x^{2}$

A projectile is given an initial velocity of $(\hat i+2\hat j)\,m/ s$ where $\hat i$ is along the ground and $\hat j$ is along the vertical. If $g = 10\,m/s^2,$ the equation of its trajectory is

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