The equation of a projectile is y=sqrt{3} x-f | vedclass

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Question

$y = x	an 	heta - \frac{{g{x^2}}}{{2{u^2}{{\cos }^2}	heta }}$

$\frac{g}{{2{u^2}{{\cos }^2}	heta }} = \frac{1}{2}$

$	heta = 60^o$

$u = 2\

Vedclass · Accepted Answer

$2\sqrt {10} \,m/s$

Vedclass · Answer

$y = x	an 	heta - \frac{{g{x^2}}}{{2{u^2}{{\cos }^2}	heta }}$

$\frac{g}{{2{u^2}{{\cos }^2}	heta }} = \frac{1}{2}$

$	heta = 60^o$

$u = 2\sqrt {10} \,m/\sec $

The equation of a projectile is $y=\sqrt{3} x-\frac{ x^2}{2}$, the velocity of projection is

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