$A$ positive charge $q$ is kept at the center of a thick shell of inner radius $R_1$ and outer radius $R_2$ which is made up of conducting material. If $\phi_1$ is the flux through a closed Gaussian surface $S_1$ whose radius is just less than $R_1$ and $\phi_2$ is the flux through a closed Gaussian surface $S_2$ whose radius is just greater than $R_1$,then:

  • A
    $\phi_1 > \phi_2$
  • B
    $\phi_2 > \phi_1$
  • C
    $\phi_1 = \phi_2 = \frac{q}{\varepsilon_0}$
  • D
    $\phi_1 = \phi_2 = 0$

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The electric field in a region of space is given by $\overrightarrow E = E_0 \hat i + 2E_0 \hat j$,where $E_0 = 100 \, N/C$. The flux of the field through a circular surface of radius $0.02 \, m$ parallel to the $Y-Z$ plane is nearly:

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If the radius of the spherical Gaussian surface is increased,then the electric flux due to a point charge enclosed by the surface:

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